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1.2x^2+29.4x-890.7=0
a = 1.2; b = 29.4; c = -890.7;
Δ = b2-4ac
Δ = 29.42-4·1.2·(-890.7)
Δ = 5139.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29.4)-\sqrt{5139.72}}{2*1.2}=\frac{-29.4-\sqrt{5139.72}}{2.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29.4)+\sqrt{5139.72}}{2*1.2}=\frac{-29.4+\sqrt{5139.72}}{2.4} $
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